If log x*2-9x+7=3 find the value of x
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Given: log₃ (x² - 9x + 7) = 3
To find : Value of x
Solution:
log₃ (x² - 9x + 7) = 3
as we know that
logₐb = n
=> aⁿ = b
Using this
x² - 9x + 7 = 3³
=> x² - 9x + 7 = 27
=> x² - 9x - 20 = 0
=> x = (9 ± √(9² - 4(1)(-20) ) /2
=> x = (9 ± √161 ) /2
x = (9 ± √161 ) /2
x = (9 ± √161 ) /2 if log₃ (x² - 9x + 7) = 3
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