if log x=2 log a + 3 log b - log c, then x=
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logx = 2loga +3 logb - logc
use concept of logarithm function .
logm + logn = logmn
logm - logn = logm/n
nlogm = logn^m
now,
logx = loga² +logb³ - logc
logx = log(a²b³/c)
x = a²b³/c
use concept of logarithm function .
logm + logn = logmn
logm - logn = logm/n
nlogm = logn^m
now,
logx = loga² +logb³ - logc
logx = log(a²b³/c)
x = a²b³/c
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