Question

If log(x-2) + log(x-3) = log 2 then the values of x are​

Answer 1

Answer:

Step-by-step explanation:

log(x-2)+log(x-3)=log 2

log((x-2)*(x-3))=log 2

x^2 -5x +6 =2

x^2 -5x +6 -2=0

x^2 -5x +4=0

x^2 -4x -x +4=0

(x-4)(x-1)=0

x=4,1