if log(x^2+y^2)=log^2+log^x+log^y then prove that x=y
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log(x^2+y^2)=log^2+log^x+log^y
log(x^2+y^2)=log(2xy)
x^2+y^2=2xy(x^2+y^2)
(x^2+y^2-2xy)=0
(x-y)^2=0
x-y=0
x=y
ALL THE BEST
-JAKKA1729
log(x^2+y^2)=log(2xy)
x^2+y^2=2xy(x^2+y^2)
(x^2+y^2-2xy)=0
(x-y)^2=0
x-y=0
x=y
ALL THE BEST
-JAKKA1729
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