if log (x^3 - y^3/x^3 + y^3) = a, prove that dy/dx=y/x
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log10(x3−y3x3+y3)=2
∴x3−y3x3+y3=102=100
∴x3−y3=100x3+100y3
∴101y3=−99x3∴y3=−99101x3
Differentiating both sides w.r.t. x, we get,
3y2dydx=−99101×3x2
∴dydx=−99x2101y2
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