if log x base 2 +log x base 4 +log x base 16 equal to 7 divided by 4 then find x
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Answered by
1
Answer:
We know that log
a
n
N=
n
1
log
a
N.
Now,
log
2
x+log
4
x+log
16
x=
4
21
⇒log
2
x+log
2
2
x+log
2
4
x=
4
21
⇒log
2
x+
2
1
log
2
x+
4
1
log
2
x=
4
21
,
⇒(1+
2
1
+
4
1
)log
2
x=
4
21
⇒
4
7
log
2
x=
4
21
⇒log
2
x=3
Hence, x=2
3
=8
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