if log x base 2 + log x base 4 + log x base 16 is equal to 21 by 4 then x is equal to
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log x at base 2 + 1/2 log of x at base 2 + 1/4 log of x at base = 21/4
log of x at base 2 ( x * ✓x * fourth root of x ) = log of 2^21/4 at base 2
x^7/4 = 2^21/4
solving it we get
x= 2^3= 8
log of x at base 2 ( x * ✓x * fourth root of x ) = log of 2^21/4 at base 2
x^7/4 = 2^21/4
solving it we get
x= 2^3= 8
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