If log x base √3=4 then x=
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Answer:
1 ) log x ( base 4 ) = log x/ log 4
= logx /log 2²
= log x/( 2log 2)
= 1/2 × log x ( base 2 )
2 ) log x ( base 16 )
= logx /log 16
= log x / log 2⁴
= log x /4log2
= 1/4 × log x ( base 2 )
Now ,
log x( base 2 ) + logx ( base 4 ) + logx( base 2 ) = 21/4
log x ( base 2 ) + 1/2 [ logx ( base 2 )] + 1/4[log( base 2 ) ] = 21/4
logx ( base 2 ) [ 1 + 1/2 + 1/4 ] = 21/4
log x( base 2 ) [ (4 +2 + 1 )/4 ] = 21/4
( 7/4 ) log x ( base 2 ) = 21/4
log x ( base 2 ) = ( 21 × 4 )/ ( 4 × 7 )
log x ( base 2 ) = 3
x = 2³
x = 8
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