Math, asked by dhanu1311, 11 months ago

if log x base 8 = 0.6, then what is the value of x is​

Answers

Answered by jayantsingh94
1

Answer:

hello ,

Here, x= 8^3/5 .

Thank you! !

Answered by Rameshjangid
0

Answer:

   The value of x = 4.

Explanation:

  • Logarithms are the other way of writing exponents. A logarithm of a number with a base is equal to an another number. A logarithm is just the opposite function of exponentiation function.

Hence, we can say that; log_{b} (x) = n    (or)    b^{n} = x

Where 'b' is the base of the logarithmic function.

This can read as “Logarithm of x to the base b is equal to n”.

  • A logarithm can be defined as the power to which a number must be raised to get some other values. It is the most appropriate way to express large numbers.
  • The logarithm of a positive real number "a" with respect to base "b", a positive real number not equal to 1^{[nb1]}, is the exponent by which "b" must be raised to give "a".
  • Given that log (x) base 8 = 0.6 and we want to find the value of x.

㏒₈ (x) = 0.6 ......... equation (1)

x = 8^{0.6}

  • 0.6 can be rewrite into a fractional. That is \frac{2}{3} = 0.6
  • Therefore, equation (1) can be written as;

㏒₈ (x) = \frac{2}{3}

∴ x = 8^{\frac{2}{3} }

  • We know that 8 is the cube of 2. That is 8 = 2^{3}

⇒ x = (2^{3} )^{\frac{2}{3} } = (2)^{2}

x = 4

  • Therefore, the value of x = 4.

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https://brainly.in/question/8067185

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