Question

If log x _ log 36 - log 64, what are the values of x and you
log5 log 6
logy
respectively?​

Answer 1

Step-by-step explanation:

logx=log36 -log 64

if there is not base

it belongs to base 10

x. 36 64

log =log -log

10 10 10

log a-b to the base 10=log a/b to the base 10

logx to the base 10 =log36/64 to the base 10

logx=log9/16

x=9/16