If log x/log 5=log y^2/log 2=log 9/log 1/3 find "x" and "y"help plz❤️
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log x /log 5 = logy^2/log2 = log 9/1/3
log x - log5 = log y^2 - Log2 = log 3^3
value of x
log x - log5 = log 3^3
log x = log 27 + log 5
x = (27×5) = 135
value of y
logy^2-log2=log27
logy^2 = log27 + log 2
y^2 = (27×2) = 54
y = root over 54
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