if log x +log (l+x)=0
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7
Log(x)+log(1+x)=0......(1)
log(a)+log(b)=log(ab)
..(1).=>>>. log(x)(1+x)=0
=> x^2+x=1
(since log1 =0)
x^2-x-1=0
nish91:
the answer should b xsquare+x-1 =0
Answered by
3
if logx+ log (l+x) =0
then log (x+x^2)=0
or x+x^2=1
x^2 +x-1=0
x= (-1+root5)/2 or x=( -1-root5)/2
then log (x+x^2)=0
or x+x^2=1
x^2 +x-1=0
x= (-1+root5)/2 or x=( -1-root5)/2
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