Question

If log x + log(x-1) = log (3x+12), then find the value of x.​

Answer 1

Given that,

log x + log(x-1) = log (3x+12)

To find,

The value of x.

Solution,

Using property : $\text{log a}+\text{log b}=\text{log ab}$

If we compare with given problem,

a = x, b = (x-1).

Using this property LHS,

$\text{log [x(x-1)]}=\text{log [3x-12]}$

or

$x(x-1) = 3x+12\\\\x^2-x-3x-12=0\\\\x^2-4x-12=0\\\\x^2-6x+2x-12=0\\\\x(x-6)+2(x-6)=0\\\\(x-6)=0\ \text{and}\ (x+2)=0\\\\x=6\ \text{and}\ x=-2$

Neglecting x = -2, we get the value of x is 6.

Answer 2

Answer:

log_(5)(2x+4)=2

Step-by-step explanation: