If log x to the base 4 + log x to the base 2 = 6 then the value of x is?
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log x to base 2 can be written as log x^2 to base 4. so the equation is
log x + log x^2 with base as 4.
acc. to log m + log n with same base = log mn to same base
log x^3 to base 4 = 6
from this we can write x^3 = 4 ^6
apply cube root both sides.
x = 4^2
x =16
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