Question

if log(x+y)=1/2
log xy prove that x^2+y^2 =3xy. don't need to answer if you don't know​

Answer 1

Answer:

log(x-y)=1/2log xy

Step-by-step explanation:

log(x-y)=log xy^1/2

x-y= xy^1/2

(x-y)^2=xy

x^2+y^2-2xy=xy

x^2+y^2=3xy