if log (x-y)/2 =1/2(log x+log y) prove that x^2 +y^2=6xy
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log(x-y)/2 = 1/2( logx + logy)
log (x-y) / 2 = 1/2logxy
x-y/2 = √xy
x-y = 2√xy
Squaring on both sides;
x²+y²-2xy =4xy
x²+y² = 6xy .
Hence proved !
log (x-y) / 2 = 1/2logxy
x-y/2 = √xy
x-y = 2√xy
Squaring on both sides;
x²+y²-2xy =4xy
x²+y² = 6xy .
Hence proved !
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