Math, asked by bokkadharmaraju879, 9 months ago

if log (x + y \ 3) =1 \2 ( log x + log Y) then find the value of x\y+y/x​

Answers

Answered by sunilkumar42904
11

Answer:

answer is 7.

Step-by-step explanation:

log (x+y/3) =1/2. (log x + log y )

log (x+y/3) = log √xy

remove the log anther both side

(x+y/3) =√xy

(x+y/3)^2 =xy

x^2+y^2+2xy/9 = xy

x^2+y^2+2xy = 9 xy

x^2 +y^2 = 9xy-2xy

x^2+y^2 = 7 xy ----------------------(1)

from the another

= x/y +y/x

= x^2 + y^2/xy from (1)

= 7xy/xy

= 7

Answered by smartyketan
0

Answer:

7

Step-by-step explanation:

by applying limit you get

some equations by solving

them you will get 7 as

in above a person has given

I hope it was helpful

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