if log (x + y \ 3) =1 \2 ( log x + log Y) then find the value of x\y+y/x
Answers
Answered by
11
Answer:
answer is 7.
Step-by-step explanation:
log (x+y/3) =1/2. (log x + log y )
log (x+y/3) = log √xy
remove the log anther both side
(x+y/3) =√xy
(x+y/3)^2 =xy
x^2+y^2+2xy/9 = xy
x^2+y^2+2xy = 9 xy
x^2 +y^2 = 9xy-2xy
x^2+y^2 = 7 xy ----------------------(1)
from the another
= x/y +y/x
= x^2 + y^2/xy from (1)
= 7xy/xy
= 7
Answered by
0
Answer:
7
Step-by-step explanation:
by applying limit you get
some equations by solving
them you will get 7 as
in above a person has given
I hope it was helpful
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