Question

if log (x+y)/3=1/2(logx+log y)​

Answer 1

Answer:

log (x+y)/7 =1/2 (log x+logy)

log (x+y)/7=1/2 log(xy)

log (x+y)/7 = log((xy)^0.5)

Now logs get cancelled

(x+y)/7= (xy)^0.5

Squaring on both side we get

(x^2+2xy+y^2)/49=xy

Taking xy of lhs on rhs and 49 on rhs

(x^2+2xy+y^2)/xy=49

(x/y+2+y/x)=49

(x/y+y/x)=49–2

(x/y+y/x)=47

Step-by-step explanation:

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