Question

if log[x+y÷3]=1÷2(logx+logy),then find the value of x÷y+y÷x​

Answer 1

Answer:

Hola‼..........❤✌

log(x+y/3)=1/2(logx+logy)

=>2logx+y/3=logx+logy

=>log(x+y)²/3²=logxy

=>logx²+y²/9=logxy

Cancel the logs on both sides

=>x²+y²/9=xy

=>x²+y²+2xy=9xy

=>x²+y²=9xy-2xy

=>x²+y²=7xy

Divide the xy on all

=>x²/xy+y²/xy=7xy/xy

=>x/y+y/x=7

Hope it’s helpful....... ☺