If log(x+y)/3=1/2(logx+logy),then find the value of (x/y)+(y/x)
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Given : log (x+y)/3 = 1/2 (logx+logy)
= 1/2 (logxy)
= log (xy)^1/2
Therefore, x+y/3 = xy^1/2
=> x+y = 3 xy^1/2
SOBS
(x+y)^2 = (3 xy^1/2)^2
x^2 + y^2 + 2xy = 9xy
x^2 + y^2 = 7xy
x^2 + y^2 /xy = 7
Therefore,
x/y + y/x = 7.
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