Question

if log (x+y/3)=1/3 ( log x + log y ), then find the value of 1/x - 1/y
​

Answer 1

Answer:

log [ ( x + y )/3] = 1/2 ( logx + logy)

2× log[ ( x + y )/3 ] = log x + log y

log [ ( x + y ) / 3 ]^2 = log xy

{ since i ) n log a = log a^n

ii ) log a + log b = log ab }

Remove log bothsides,

[ ( x + y ) / 3 ]^2 = xy

( x + y )^2 / 3^2 = xy

x^2 + y^2 + 2xy = 9xy

x^2 + y^2 = 9xy - 2xy

x^2 + y^2 = 7xy

Divide each term with xy

x^2 / xy + y^2 / xy = 7xy / xy

x / y + y / x = 7

I hope this help you.

plz mark as brainliast answer

Answer 2

Answer:

ya wala question sir kaa upper se nikal gaya sorry for it