Question

if log (x-y)=log x-logy, then show that x=y 2 ​/y-1

Answer 1

go through the solution

Answer 2

Step-by-step explanation:

Given : log (x-y)= logx-logy

to show : x=y^2/y-1

• log (x-y) = logx-logy
• log(x-y) = logx/y 【loga-logb =loga/ logb】
• x-y = x/y 【cancelation the both logs 】
• (x-y) y = x 【transposing y to the left hand side
• xy-y^2 = x
• xy- x = y^2
• x(y-1) = y^2

therefore, x = y^2/y-l

hence, proved