Question

if log(x+y)=logx +logy,then x=?​

Answer 1

Step-by-step explanation:

Given :-

log(x+y)=log x +log y

To find :-

Find the value of x ?

Solution :-

Given that

log (x+y) = log x +log y

We know that

log ab = log a + log b

=> log (x+y) = log (xy)

=> x+y = xy

=> x + y - xy = 0

=> (x-xy) + y = 0

=> x(1-y) + y = 0

=> x(1-y) = -y

=> x = -y/(1-y)

=> x = y/(y-1)

Therefore, x = y/(y-1)

Answer:-

The value of x for the given problem is

y/(y-1)

Used formulae:-

→ log ab = log a + log b