Question

If log x³²=5, find value of x​

Answer 1

$\huge\star{\tt{\underline{\underline{\red{Answer}}}}}\star$

Log$_{x}^{32}$ = 5

$\implies$ 32 = x${}^{5}$

$\implies$ 32 = 2 x 2 x 2 x 2 x 2 = 2${}^{5}$

so

x${}^{5}$ = 2${}^{5}$

Therefore,

$\large{\boxe{\boxed{x=5}}}$