Question

if log(xsquare5+4)then find dy/dx

Answer 1

Answer: 10x / (  5x^2 +4 )

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Step-by-step explanation:

Given function, y= log ( 5x^2 +4 )

now,

dy / dx = d( log ( 5x^2 +4 ) ) /dx

            = d ( log ( 5x^2 +4 ) ) /d  ( 5x^2 +4 ) * d ( 5x^2 +4 ) /d x

            = 1 /(  5x^2 +4 ) * 10 x

            = 10x / (  5x^2 +4 )