If log xy = 0.9 and log x/y = 0.5 then log square root y = ?
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Answer:
logx/logy = 3/2, log(xy) = 5,
logx = 3/2 logy —————->eqn 1
log(xy) = log x + log y
log x + log y = 5, —————->eqn 2
Substitute eqn 2 in eqn 1!
3/2 logy + log y = 5,
5/2 log y = 5 , cancel 5 on both sides
log y = 2
log has base 10 so y is given by
y = 10 pow(2)
y = 100
Substitute y = 100 in eqn 2
log x + logy = 5
log x + log (100) = 5
log x + 2 = 5
log x = 3 , log has a base of 10 x given as
x = 10 pow(3)
x = 1000.
Hence x=1000, y = 100
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