Question

If log (
×/y) + log (y/x) =log (x+y)
then _______.
a . x+y=1
b. x-y= 1
c. x = y
d. x^2 - y^2 = 1​

Answer 1

Step-by-step explanation:

log(x/y) + log(y/x) = log (y/x×x/y ) = log1 = 0

so , 0 = log (x+y)

After remove the log

10^0 = x+y

so, Finally , x+y = 1

Answer 2

log(x/y) + log(y/x) = log(x+y)

=> logx - logy + logy - logx = log(x+y)

=> log(x+y) = 0

$= > x + y = {e}^{0} \\ \\ = > x + y = 1$

So, option (a) x+y = 1 is correct ✔️✔️