Question

if log y = tan^-1x then find the value of y3 at x=0 is ?

Answer 1

Step-by-step explanation:

Answer

y=tan

−1

x

x=tany

Differentiating w.r.t.y, we get

dy

dx

=sec

2

y

Diff both sides w.r.t x,

dx

2

d

2

y

=

dx

d

(cos

2

y)

dx

2

d

2

y

=−2cosysiny

dx

dy

dx

2

d

2

y

=−2cosysiny×cos

2

y

dx

2

d

2

y

=−2sinycos

3

y