Question

if log¹⁰125+log¹⁰8=x,then x=?​

Answer 1

Step-by-step explanation:

Given :-

log¹⁰125+log¹⁰8=x

To find :-

Find the value of x ?

Solution :-

Given that

log¹⁰125+log¹⁰8=x

We know that

log ab = log a + log b

=> log¹⁰ (125×8) = x

=> log¹⁰ 1000 = x

=> log¹⁰ (10×10×10) = x

=> log¹⁰ (10³) = x

=> 3 log¹⁰ 10 = x

Since log a^m = m log a

=> 3 × 1 = x

Since log a (a) = 1

=> 3 = x

=> x = 3

Therefore, x = 3

Answer:-

The value of x for the given problem is 3

Used formulae:-

→ log ab = log a + log b

→ log a^m = m log a

→ log a (a) = 1