if log1/2(x) is greater than or equal to 0 then x belongs to?
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(4−x)≥log
1/2
2−log
1/2
(x−1)
Where, 4−x>0 & x−1>0⇒x∈(1,4)⇒(1)
⇒log
2
(4−x)≤log
2
2−log
2
(x−1)[∵log
a
n
b
m
=
n
m
log
a
b]
⇒log
2
(4−x)≤log
2
x−1
2
[∵loga−logb=log
b
a
]
⇒(4−x)(x−1)≤2
⇒x
2
−5x+6≥0
⇒x≥3 or x≤2⇒(2)
Therefore, using (1) and (2)
x∈(1,2]∪[3,4)
Ans: A,B
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