Question

If log10 2 = 0.3010, the value of log10 80 is:
A.1.602
B.1.903
C.3.903
D.None of these

Answer 1

$hi \: mate \\ \\ \\ log_{10}(80) = log_{10}(10) + 3log_{10}(2) \\ \\ log_{10}(80) = 1 + 3(0.3010) \\ \\ log_{10}(80) = 1.903 \\ \\ \\ \\ have \: a \: nyc \: tym$

Answer 2

Answer:

The value of log₁₀80 = 1.903

Step-by-step explanation:

Given log₁₀2 = 0.3010

To find the value of log₁₀80

80 can be written as $8\times 10$

Therefore,

$log_{10} 80=log_{10} (8\times 10)$

Using  log₁₀ab=log₁₀a + log₁₀b

$log_{10} (80)=log_{10}8+log_{10}10$

Using logₐ(a)=1

$log_{10} (80)=log_{10}8+1$

8 can be written as cube of 2

$log_{10} (80)=log_{10}2^{3} +1$

Using log₁₀(aᵇ)=blog₁₀a

$log_{10} (80)=3log_{10}2 +1$

Substituting the value of log₁₀2 = 0.3010

$log_{10} (80)=3\times 0.3010 +1$

$log_{10} (80)= 0.903 +1=1.903$

Therefore, the value of log₁₀80 = 1.903

So, the correct answer is option B.

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