Question

If log10 4 = 0.6020 and log10 3 = 0.4771, what is the value of log10 12?

Answer 1

log10 (12) = log10 (4 x 3) = log10 (3) + log10 (4)

= 0.4771 x 0.602 = 0.2872 ..... ans...

Answer 2

Answer:

$\log_{10}12=1.0791$

Step-by-step explanation:

Given : $\log_{10}4=0.6020$ and $\log_{10}3=0.4771$

To find : What is the value of $\log_{10}12$ ?

Solution :

We can write the expression as,

$\log_{10}12=\log_{10}(4\times 3)$

Applying logarithmic property, $\log(ab)=\log a+\log b$

$\log_{10}12=\log_{10}4+\log_{10}3$

Substitute the given values,

$\log_{10}12=0.6020+0.4771$

$\log_{10}12=1.0791$

Therefore, The value is $\log_{10}12=1.0791$