Question

if log10 (98+√x²- 12x+36 ) = 2 then x=?​

Answer 1

Answer

$x=12$

Step-by-step explanation

$\log _{10}\left(10\right)\left(98+\left(\sqrt{x}\right)^2-12x+36\right)=2$

$\to 1\cdot \left(-12x+\left(\sqrt{x}\right)^2+98+36\right)=2$

$\to 1\cdot \left(-12x+x+98+36\right)=2$

$\to-12x+x+98+36=2$

$\to-11x+98+36=2$

$\to-11x+134=2$

$\to-11x+134-134=2-134$

$\to-11x=-132$

$\to x=12$