Question

If log10 a+1/2log10 , b=1 then a^2b is​

Answer 1

Answer:

If log a +1/2logb =1, how can I prove that ba²=100?

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Hello!!!

loga+0.5*logb=1

Now using property a*logb=log(b^a)

loga+log(b^0.5)=1

Now using property log(a*b)=loga+logb

log(a*b^0.5)=1

Taking antilog on both sides

a*b^0.5=10^1

a*b^0.5=10

Now squaring on both side we get

(a^2)*b=100

Hope dis may help u.