Question

If log10(x^2 - y^2/x^2+ y^2)=2, then dy/dx=?​

Answer 1

Answer:

let try

Step-by-step explanation:

1/x^2-y^2(2x-2ydy/dx)-1/x^2+y^2(2x+2ydy/dx)=0

2x-2ydy/dx/x^2-y^2-2x+2ydy/dx/x^2+y^2=0