Question

If log10 (x+3) + log10, 2 =1, then find the value of 'x'.​

Answer 1

Use the product rule
(X+3) (2) = 10
2x + 6 = 10
2x = 10-6
X = 4/2 = 2

Answer 2

The value of x = 2

Step-by-step explanation:

We have,

$\log_{10}(x+3)+\log_{10}2=1$

To find, the value of x = ?

∴ $\log_{10}(x+3)+\log_{10}2=1$

⇒ $=\log_{10}(x+3)+\log_{10}2=\log_{10}10$

[ ∵ $\log_{10}10=1$]

⇒ $\log_{10}(x+3).(2)=\log_{10}10$

[ ∵ $\log m+\log n=\log mn$]

Equating both sides equal base, we get

⇒ $(x+3)2=10$

⇒ $x+3=\dfrac{10}{2}=5$

⇒ x = 5 - 3 = 2

∴ x = 2

Hence, the value of x = 2