If [log101] + [log102] + [log103] + [log104] + ...... + [log10n] = n,
where [x] denotes the greatest integer less than or equal to x, then
(1) 96 ≤ n < 104
(2) 104 ≤ n < 107
(3) 107 ≤ n < 111
(4) 111 ≤ n < 116
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Answer:
the correct answer is (3) 107 ≤ n < 111
Step-by-step explanation:
log₁₀1 = 0
log₁₀10 = 1
log₁₀100 = 2
since [x] denotes the greatest integer less than or equal to x
=> [log₁₀2] = [log₁₀3] = .......... = [log₁₀9] = 0
=>[log₁₀1] + [log₁₀2] + [log₁₀3] + .......... + [log₁₀9] = 0
also,
[log₁₀10] = [log₁₀11] = ................ = [log₁₀99] = 1
=> [log₁₀10] + [log₁₀11] + ................ + [log₁₀99] = 90
also
[log₁₀100] = [log₁₀101] = [log₁₀102] = .........................= [log₁₀999] = 2
hence ,
[log₁₀1] + [log₁₀2] .....+ [log₁₀9] + [log₁₀10] + ...... + [log₁₀99] + [log₁₀100] + ...... [log₁₀n] = n
=> 0 + 90 + [log₁₀100] + ...... [log₁₀n] = n
=> 90 + 2(n - 99) = n
=> 2n - n - 198 + 90
=> n = 108
Hence the correct answer is (3) 107 ≤ n < 111
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