Question

If log10p=x , log10q=y , find i) pq ii) p/q

Answer 1

Answer:

log 10 to base p=x

=>10^x=p

log 10 to base q=y

=>10^y=q

i)pq=(10^x) ×(10^y)

=(10)^x+y

ii)p/q=10^x/10^y

=(10)^x-y