Question

if log10x=p and log 10y=q,show that xy=(10)^p+q​

Answer 1

Answer:

QUESTION :-

$log_{10}(x) = p$

$log_{10}(y) = q$

TO PROVE :-

$xy = {10}^{(p + q)}$

SOLUTION :-

ADD THE GIVEN EQUATIONS =》

$log_{10}(x) + log_{10}(y) = p + q$

NOW USE LOGARITHMIC PROPERTY –

$log_{10}(x + y) = p + q$

WE KNOW THAT –

$if \: \: \: log_{e}(p) = n \: \: \: then \: \: \: p = {e}^{n}$

SO ,

$x + y = {10}^{(p + q)}$

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