If log1227 = a, log916 = b, find log8108.
\\frac{2(a + 3)}{3b}\\)
\\frac{2(a + 3)}{3a}\\)
\\frac{2(b + 3)}{3a}\\)
\\frac{2(b + 3)}{3b}\\)
Anonymous:
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Answer:2(b+3)3b
Step-by-step explanation:
log8108 = log8(4 * 27)
log8108 = log84 + log827
=> log84 = 23
log827 = log1627log168
log827 = log16273/4
log827 = 43 log1627
log827 = 43 log927log916
log827 = 43 frac32log916
log827 = 2 * log169
log916 = b
log169 = 1b
log827 = 2b
log8108 = 23 + 2b
= 2(13 + 1b)
= 2(b+3)3b.
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