Question

If log125/27=p(log5-log3) then find the value of p2-3p+1​

Answer 1

Answer:

19 is the answer please mark this answer as brainliest answer

Answer 2

Answer:1

Step-by-step explanation:

Log(125/27) = log(5/3)^3 = 3log(5/3) = 3 ( log5 - log3)

Log(125/27) = p(log5-log3)

3 (log5-log3) = p(log5-log3)

p = 3.

p^2 - 3p + 1 = 3*3 - 3*3 + 1 = 9-9+1 = 1.