if log2=0.3010 and log 3=0.4771 find the value of log 25
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Answered by
292
Log25 = log5 + log5
= log(10/2) + log(10/2)
= (log10-log2) + (log10-log2)
= (1-0.3010) + (1-0.3010)
= 0.6990 + 0.6990
= 1.3980
= log(10/2) + log(10/2)
= (log10-log2) + (log10-log2)
= (1-0.3010) + (1-0.3010)
= 0.6990 + 0.6990
= 1.3980
Answered by
108
"From the details details, the value of log2 and log 3 is given below. It is 0.3010 and 0.4771 respectively. Then the value of log 25 is calculated below.
Log25 = log5 + log5
= log(10/2) + log(10/2)
= (log10-log2) + (log10-log2)
= (1-0.3010) + (1-0.3010)
= 0.6990 + 0.6990
The value of log 25 is 1.3980.
"
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