Question

If log2=0.3010 and log 3=0.4771 find the value of log 64/16

Answer 1

Answer:0.6020

Explanation:

log(64/16)

=log(4)

= log(2^2) = 2× log(2

)= 2×0.3010=0.6020

OR

log(64/16)=log(64)-log(16)

=log(2^6)-log(2^4)

=6×log(2)-4×log(2)

=6×0.3010-4×0.3010

=0.3010(6-4)=0.3010×2=0.6020