Question

If log2=0.3010 and log 3=0.4771 find the values of log root24

Answer 1

Answer:

log root 24 =0.69005

Step-by-step explanation:

log (24)1/2= 1/2 log (24)

                = 1/2[ log(4) + log (6)]

                =1/2 [ log 2^^2 + log 2 + log 3]

               =0.5 [2(0.3010) + 0.3010 + 0.4771]

                =0.5[1.3801]

                 =0.69005

log(a+b)=log(ab)

log (a)^b = b log (a)