Question

If log2=0.3010 and log3=0.4771. Find the value of log 24 and log 162

Answer 1

Hi Friend !!!



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log 24 = log 2×2×3

= log2 + log2 + log3

= 0.3010+0.3010+0.4771

= 1.0791

log 162 = log 2×3×3×3×3

= log 2+log3+log3+log3+log3

= 0.3010+4(0.4771)

= 2.2094


Hope it helps u :-)

Answer 2

Answer:

The values of log 24 and log 162 is

log 24 = 1.3801

log 162 = 2.2094.

Step-by-step explanation:

Given:

log 2 = 0.3010 and log 3 = 0.4771

To find:

the value of log 24 and log 162.

Step 1

Let, log 2 = 0.3010 and log 3 = 0.4771 then

log 24 = log (2×2×2×3)

Simplifying the above equation, we get

log 24 = log 2 +log 2+ log 2+ log 3

log 24 = 0.3010 + 0.3010 +0.3010 + 0.4771

Thus, log 24 = 1.3801

Step 2

If log 2 = 0.3010 and log 3 = 0.4771 then

log 162 = log (2× 3×3×3×3)

Simplifying the above equation, we get

log 162= log 2 + log 3 +log 3 +log 3+log 3+ log3

log 162 = 0.3010 + 0.4771+0.4771+0.4771+0.4771

Thus, log 162 = 2.2094

Therefore, the values of log 24 and log 162 is

log 24 = 1.3801

log 162 = 2.2094.

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