If log2= 0.3010 and log3 =0.4771, log512 on base 5 will be??
Answers
Answered by
1
log512 to base 5
=log 512/log 5 both base is 10
=9 log 2/log 10-log 2
=9×0.3010/1-0.3010
=log 512/log 5 both base is 10
=9 log 2/log 10-log 2
=9×0.3010/1-0.3010
futureflame43:
tnx
Thnk u too
Similar questions