Question

If log2 = 0.3010 find the number of digits in 2^64

Answer 1

Answer:

64xlog2

=64x0.3010

=19.126

Number of digits is 20

Answer 2

Answer: Required number of digit is 20.

Step by step explanation

Given,

$log(2) = 0.3010$

$log_{10}( {2}^{64} ) = 64 \times log_{10}(2) = 64 \times 0.3010 = 19.264$

→${2}^{64} = {10}^{19.264}$

The number of digits in ${10}^{19}$ is 20, there will be 21 digit from ${10}^{21}$

The number ${10}^{19.264}$

lies between them.Therefore the number of digits in ${10}^{19.264}$ is 20.