Math, asked by aniket17994, 8 months ago

if log2=0.3010,log3=0.4771, log7=0.8450,find the value oflog 84

Answers

Answered by EMATH4U

0

Answer:

We know that log(abc..)=loga+logb+logc+....

log(84)=log(2×2×3×7)
=log2+log2+log3+log7
=0.3010+0.3010+0.4771+0.8450
=1.9241

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