Question

If log2=0.3010 then log 32=

Answer 1

$log(2) = 0.3010 \\ \\ log(32) \\ \\ = log( {2}^{5} ) \\ \\ = 5 log(2) \\ \\ = 5(.0301) \\ \\ = 1.505 \\ \\ since \: mloga = log {a}^{m}$

hope it helps

Answer 2

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