Question

if log2 (5x+1)=5, then find x​

Answer 1

divide both sides by 5. 5x + 1 = 2 ( x + 5 ) = 2x + 10. Collect terms. 5x - 2x = 10 – 1. 3x = 9. x = 3. However if as I did, initially read the questions as = log(x+5) to

Answer 2

Required Answer:-

Given:

• $\sf log_{2}(5x + 7) = 5$

To Find:

• The value of x.

Solution:

$\sf log_{2}(5x + 7) = 5$

$\sf \implies {2}^{5} = 5x + 7$

$\sf \implies 5x + 7 = 32$

$\sf \implies 5x = 32 - 7$

$\sf \implies 5x = 25$

Dividing both sides by 5, we get,

$\sf \implies x = 5$

Hence, the value of x is 5.

Answer:

• The value of x is 5.

Formula Used:

• $\sf log_{a}(n) = b \implies a^{b} = n$